Abstract
Background
Assessing the non-random associations of alleles at different loci, or gametic disequilibrium, can provide clues about aspects of population histories and mating behavior and can be useful in locating disease genes. For gametic data which are available from several strata with different allele probabilities, it is necessary to verify that the strata are homogeneous in terms of gametic disequilibrium.
Results
Using the likelihood score theory generalized to nuisance parameters we derive a score test for homogeneity of gametic disequilibrium across several independent populations. Simulation results demonstrate that the empirical type I error rates of our score homogeneity test perform satisfactorily in the sense that they are close to the pre-chosen 0.05 nominal level. The associated power and sample size formulae are derived. We illustrate our test with a data set from a study of the cystic fibrosis transmembrane conductance regulator gene.
Conclusion
We propose a large-sample homogeneity test on gametic disequilibrium across several independent populations based on the likelihood score theory generalized to nuisance parameters. Our simulation results show that our test is more reliable than the traditional test based on the Fisher's test of homogeneity among correlation coefficients.
Background
Measuring gametic disequilibrium can provide important information about aspects of population histories and mating behavior [1] and can be useful in locating disease genes [2]. The term gametic disequilibrium is used in this article instead of the traditional term linkage disequilibrium to measure the extent of non-random association because such non-random association may be present between unlinked loci [3]. Various measures of gametic disequilibrium have been proposed [4-6], ranging from pairs of diallelic loci model to multiple multiallelic loci model. In this article, we consider the gametic disequilibrium which is defined as the difference between the gametic probability and its expected probability under the assumption of no statistical association of alleles, and the gametic disequilibrium calculations are based on two-allele, two-locus model [7].
Consider two loci, A and B, each having two possible alleles (A0, A1) and (B0, B1), respectively. With two loci and two alleles, there are four possible gametes, namely, A0B0, A0B1, A1B0 and A1B1. The gametic disequilibrium between the two loci is defined by
where
and
denote the allele probabilities of Ai and Bj,
denotes the gamete probability of AiBj, i, j = 0, 1. Suppose that the gametic data are available from K strata and let pijk denote the gametic probability of array of AiBj for the k-th stratum, i, j = 0, 1; k = 1,...,K, ∑i,jpijk = 1 for each k. According to the relationship between allelic probability and gametic
probability, the allele probabilities of A0, A1, B0 and B1 are derived as p0+k, p1+k, p+0k and p+1k, respectively. Here "+" denote the summation over 0 and 1, for example, p0+k = p00k + p01k. For stratum k (k = 1,...,K), the gametic disequilibrium is calculated as
It is easy to show that Dk is bounded by
where Dk,min = -min{p1+kp+1k, p0+kp+0k}, Dk,max = min{p1+kp+0k, p0+kp+1k}. Testing for the homogeneity of gametic disequilibrium among strata can be informative in discriminating among the evolutionary agents generating them in natural population [8]. Detecting gametic disequilibrium can be informative in mapping gene and providing meaningful clues of population evolution. Combining the evidence of gametic disequilibrium across several strata may be more sufficient to support the clues, in contrast to analysis with each strata. In this case, it is crucial to test the homogeneity of gametic disequilibrium across strata before combining the data. For this purpose, it is interesting to consider the following hypothesis
Weir [9] recommended a homogeneity test on gametic disequilibrium, based on Fisher's test
of homogeneity among correlation coefficients [10]. In his method, the gametic disequilibrium Dk is first transformed to a correlation coefficient rk by rk = Dk/
, rk is then transformed to a normal variable zk by Fisher's z transformation, and a weighted sum of squares of the z values which has χ2 distribution with K - 1 degrees of freedom is finally proposed for testing homogeneity of gametic disequilibrium.
As pointed out by Zapata and Alvarez [8], this test is actually for homogeneity of r values instead of D values. They may not be equivalent when the allele probabilities are different across
strata. Instead, Zapata and Alvarez [8] suggested the use of the normalized difference D' [11]. Specifically,
is the ratio of Dk to Dk,max when Dk > 0, or the ratio of Dk to -Dk,min when Dk < 0. Zapata and Alvarez obtained the bias-corrected confidence interval for each D' value across strata via the bootstrap method. Hence, acceptance or rejection of homogeneity
of D' values can be determined by evaluating the obtained confidence intervals. For the
example considered in Zapata and Alvarez [8], there is no intersection for the confidence intervals obtained from all strata.
Hence, one has evidence to reject the null hypothesis of homogeneity. Unfortunately,
Zapata and Alvarez [8] did not discuss the decision rules for cases such as intersections exist but the
extent are different. Hence, no rigorous rule based on this confidence interval approach
was proposed and this makes their method less practicable. However, no rigorous rule
based on this confidence interval approach was proposed and this makes their method
less practicable. It should be noted that the homogeneity test of either r values or D' values is not equivalent to the homogeneity test of D values. In particular, transformation D' only guarantees that the range of D' is [-1, 1]. However, there remains difficulties in interpreting the value of D'. Lewontin [11] noted that values of D' at different loci and in different populations tend to vary with the values of the
allele probabilities, so that the problem of cross-locus and cross-population comparisons
is not fully overcome by the use of D'. In this article, without doing any transformation, we develop an asymptotic homogeneity
test directly based on D values via score method.
Methods
Homogeneity test
Let xijk (i, j = 0, 1 and k = 1,⋯,K) be the number of the gamete AiBj in the k-th stratum with the total gametes being nk = x00k + x01k + x10k + s11k. Let M(nk, {pijk}) denote the quadrinomial distribution with parameter vector (p00k, p01k, p10k, p11k)'. Thus, we have {xijk : i, j = 0, 1} ~ M(nk, {pijk}) for k = 1,...,K. The homogeneity hypothesis in (1) is of interest in this article. Here, we assume that K is fixed and nk is sufficiently large for k = 1, 2,...,K. Noticing that p00k = p0+kp+0k + Dk, p01k = p0+kp+1k - Dk, p10k = p1+kp+0k - Dk, p11k = p1+kp+1k + Dk, the log-likelihood for the k-th stratum can be expressed in terms of Dk, p1+k and p+1k (k = 1,....,K). That is,
where p0+k = 1 - p1+k, p+0k = 1 - p+1k. Let D denote the common gametic disequilibrium under H0, p1+ = (p1+1,...,p1+K)' and p+1 = (p+11,...,p+1K)' denote the nuisance parameter vectors. Under H0, the total log-likelihood for all K strata is given by
Hence, the efficient scores for the k-th stratum (i.e., the first order derivatives of lk(D, p1+k, p+1k) with respect to D, p1+k and p+1k) are given by
If
,
and
are the maximum likelihood estimates (MLEs) of D, p1+ and p+1 under H0, respectively, then they satisfy the following 2K + 1 equations:
Variances and covariances for the efficient scores are given by
Denote
Hence, the likelihood score test for the homogeneity hypothesis H0 : D1 = ⋯ = DK is given by
which asymptotically follows the chi-square distribution with K - 1 degrees of freedom under H0.
Unfortunately,
,
and
cannot be expressed in a closed form and this makes the likelihood score test X2 less appealing in practice. To overcome this issue, applying the theory of homogeneity
score test extended to nuisance parameters [12] we propose the following modified score statistic
where D*,
and
are any consistent estimators of D, p1+ and p+1, respectively. To this end, we choose D* to be
, and
and
be the solutions to the following equations
or equivalently the following quartic polynomial equations,
where
Here, D* is analogous to the well-known Mantel-Haenszel estimator [13]. It is a consistent estimator to D. In general, it is not an efficient estimator to D. The proof of consistency and the conditions for achieving asymptotic efficiency
for D* is presented in Appendix. We notice that the calculation of
in (2) is quite tedious. Nonetheless, it is easy to show that
is simply given by nk/wk(D, p1+k, p+1k) with
(see Appendix for the proof). It can be shown that X2* has an asymptotic chi-square distribution with K - 1 degrees of freedom under H0. Therefore, the homogeneity hypothesis H0 is rejected at level α when X2* ≥
, where
is the 100 × (1 - α) percentile point of the chi-square distribution with K - 1 degrees of freedom. Finally, it is noteworthy that if the consistent estimators
of D, p1+ and p+1 are the constrained MLEs under H0 then the second term of (2) vanishes, since
, and (2) reduces to the likelihood score statistic.
Asymptotic power and sample size
We will present the asymptotic power and sample size formulae based on X2* [14]. For this purpose, we assume nk = nak for some n and ak > 0. Let
,
and
be the true parameter values for Dk, p1+k and p+1k under H1, where k = 1, 2,⋯,K and
for at least a pair k ≠ j. Thus, the asymptotic power for the homogeneity score test X2* at α level is given by
where
denotes the non-central chi-square distribution with K - 1 degrees of freedom with the non-centrality parameter being
where
,
,
, p1+k and p+1k are the solutions of the following equations
where
The desirable sample size n required to attain the power at 1 - β with
,
and
being the true parameter values for Dk, p1+k and p+1k under the alternative H1 at nominal level α can be found by the relation
where
is the 100 × β percentile point of the non-central chi-square distribution with K - 1 degrees of freedom and non-centrality parameter Δ. The sample size n can be readily obtained by solving the above equation.
Availability and requirements
We have implemented the test procedures for computing our score statistic X2* in a Matlab project. Project name: gametic disequilibrium homogeneity score test (GDHST); Project home page: http://math.nenu.edu.cn/jhguo/program.htm webcite; Operating system: Windows XP; Programming language: Matlab 6.1; Licence: GNU GPL.
Results
Simulation results
To evaluate the performance of our proposed homogeneity score test, we include the homogeneity test recommended by Weir [9] in our comparison study. The corresponding test statistic for homogeneity is given by
where K is the total number of strata, nk is the total gamete number in stratum k,
is the Fisher's z transformation with
and (x00k, x01k, x10k, x11k)' being the number of the gamete array in the k-th stratum, and
is the average of the zk values.
We investigate the performance of X2* and T2 in terms of type I error rate and power. For type I error rates, we consider both
equal and unequal allele probabilities varying from 0.1 to 0.5 across (K = 3 and 5)
strata with equal sample sizes (nk = 50, 100 and 200) for k = 1,...,K and common disequilibrium (D =
Dmin, 0 and
Dmax), where Dmin = max{D1,min,...,DK,min}, Dmax = min{D1,max,...,DK,max}.
Monte Carlo simulations with 5,000 repetitions at 0.05 nominal level are summarized in Table 1, 2, 3, 4. Table 1 shows the performance of empirical type I error rates for X2* and T2 with equal allele probabilities across K = 3 strata. We observe the following.
Table 1. Empirical type I error rates for X2* and T2 for equal allele probabilities across K = 3 strata under H0
Table 2. Empirical type I error rates for X2* and T2 for unequal allele probabilities across K = 3 strata under H0
Table 3. Empirical type I error rates for X2* and T2 for equal allele probabilities across K = 5 strata under H0
Table 4. Empirical type I error rates for X2* and T2 for unequal allele probabilities across K = 5 strata under H0
1. When D is large (i.e.,
Dmax), both tests generally appear to be quite liberal (e.g., empirical size being 10
times of the nominal level), especially for small sample size (e.g., nk = 50) and small allele probability (e.g., p1+ = p+1 = (0.1, 0.1, 0.1)'). Such liberty in empirical size is more severe in T2 than in our asymptotic homogeneity test X2* and is significantly alleviated in X2* when sample size increases. However, sample size increase does not alleviate the liberty
of T2 much. In fact, even for nk = 3200 for k = 1, 2, 3, T2 is still very liberal for D = 0.045 with empirical type I errors rate being 0.456
(data are not shown).
2. For other settings, both tests perform quite satisfactorily in the sense that their empirical sizes are well controlled around the pre-chosen nominal level. In general, the larger the sample size, the closer the empirical type I error rate to the pre-chosen nominal level.
Table 2 reports the empirical size performance of X2* and T2 for unequal allele probabilities across K = 3 strata. We observe similar phenomena above. However, our asymptotic homogeneity test X2* performs quite well in all settings under consideration for moderate to large sample sizes (i.e., nk = 100 and 200) while it is not the case for T2. For T2, the resultant empirical type I error rate can be extremely inflated even for large sample design (e.g., more than 17 times of the nominal level when nk = 200 (for k = 1, 2, 3), p1+ = p+1 = (0.5, 0.3, 0.1)', and D = 0.045).
Table 3 and 4 shows the empirical type I error rate performance of X2* and T2 for K = 5. The parameter settings are similar to Table 1 and 2. According to the simulation results, liberty issue becomes more serious and larger sample sizes are required to attain similar performance when K increases from 3 to 5 under similar parameter settings.
Since many type I error rates for X2* and T2 are liberal in Tables 1 to 4. The two-sided t-test is conducted to determined if an empirical type I error rate is significantly different from the nominal lever of 0.05. The t-test statistics is
where m = 5000 and W represents the empirical type I error rate of X2* or T2. Here, the t-test is almost identical to the z-test for the sample size is very large. Those empirical type I error rates which are significantly different from the nominal level of 0.05 are underlined in Tables 1 to 4. In Table 1, the total number of significant difference from the nominal level of 0.05 for X2* and T2 is 28 and 38, respectively. The pair (28, 38) can be further decomposed to (14, 14), (8, 13) and (6, 11) according to n = 50, 100 and 200. The decreasing rate of the number of empirical type I error rates which is significant different from the nominal level of 0.05 for X2* is 14/18-6/18 = 44.4% as n increases from 50 to 200. While the corresponding decreasing rate for T2 is 14/18-11/18 = 16.7%. It is easy to see that our X2* is less liberal than T2 as sample size increases.
For Table 2, the total number of significant difference from the nominal level of 0.05 for X2* and T2 is 17 and 33, respectively. The pair (17, 33) can again be decomposed to (14, 14), (8, 13) and (6, 11) according to n = 50, 100 and 200. The decreasing rate of the number of empirical type I error rates which is significant different from the nominal level of 0.05 for X2* is 10/18-1/18 = 50.0% as n increases from 50 to 200. While the decreasing rate for T2 is 12/18-10/18 = 11.1%. The decreasing rate of our X2* is again more significant than that of T2.
In Table 3 to 4, the strata increases from 3 to 5. However, the decreasing rates of the number of empirical type I error rates which is significant different from the nominal level of 0.05 for Tables 3 and 4 is very close to that of Tables 1 and 2, respectively. Therefore, we have reason to believe that this decreasing rate is not greatly affected by the number of strata.
Table 5 summarizes the empirical powers for X2* and T2. Here, {Dk} are specified under H1 and we set Dk = D0 + δ(k - 1). For K = 3, we consider: (i) D0 = -0.03, δ = 0.03 and (ii) D0 = -0.05, δ = 0.05. For K = 5, we consider: (i) D0 = -0.06, δ = 0.03 and (ii) D0 = -0.1, δ = 0.05. From the simulation results, we observe both X2* and T2 perform similarly under the designed parameter settings. In general, powers increase with n and δ.
Table 5. Empirical powers for X2* and T2
In view of the above results, we prefer the proposed homogeneity test X2* to the traditional T2 which is based on the Fisher's test of homogeneity among correlation coefficient.
Real and hypothetical examples
It is reported that mutations at the cystic fibrosis transmembrane conductance regulator gene (CFTR) cause cystic fibrosis, the most prevalent severe genetic disorder in individuals of European descent. Mateu [15] conducted a worldwide genetic analysis of the CFTR region and analyzed normal allele and haplotype variation at two single-nucleotide polymorphisms (SNPs), namely the T854/AvaII (2694 T/G) and TUB20/PVUII (4006-200 G/A). The T854 and TUB20 markers can be used to define the core haplotypes since they are diallelic, have presumably much lower mutation rates than the other polymorphisms and the ancestral state can be inferred for them.
Mateu [15] reported the T854-TUB20 haplotype frequencies by 18 populations. After communicating with one of their coauthors (Prof. Kenneth, pers. comm. 1996), it was found that their reported gametic frequencies were actually the maximum likelihood estimates of the gametic probabilities obtained from HAPLO, a software which can be applicable to missing data. In other words, all individuals with results for at least one of the two markers were included to estimate the gametic frequencies and no actual gametic counts were available. To create the gametic counts for each population, we first estimate the total number of participants in each population by the number of individuals who yielded results for at least one of the two markers. The reported gametic frequencies of each population given in Mateu [15] are multiplied to the estimated number of participants of this population and the closest integers are then taken to be the estimated gametic counts. The estimated gametic counts across the 18 populations are reported in Table 6, which is adopted as the real data in all subsequent analysis.
Table 6. T854-TUB20 haplotype counts by 18 populations and some related statistics
It is noticed that the gametic counts for the populations of Japanese (14th) and Surui (18th) are (0, 32, 0, 12)' and (0, 7, 0, 35)', respectively and their estimated gametic disequilibrium Dk, Dk,min and Dk,max are all equal to zero. Therefore, we will exclude these two populations for subsequent homogeneity testings. We consider the following scenarios.
(i) Homogeneity of gametic disequilibrium among the 16 populations (i.e., excluding Japanese and Surui). The statistic value of our proposed X2* is 121.35 with p-value being less than 0.0001 while that of T2 yields 99.64 with p-value being less than 0.0001. In this case, both tests reject the homogeneity hypothesis at the 0.05 nominal level.
(ii) Homogeneity of gametic disequilibrium among those populations with the same numbers of participants for both markers T854 and TUB20 (i.e., Mbuti, Yemenites, Druze, Adygei, Catalans, Basques, Chinese, and Nasioi).
Our proposed statistic X2* yields 50.56 with p-value being less than 0.0001 while T2 gives 39.72 with p-value being less than 0.0001. Again, both tests suggest rejection of the homogeneity
hypothesis at the 0.05 nominal level. Suppose that another research team wants to
reconduct the same genetic analysis. In this regard, it is sensible to ask, "How large
is the sample size for each population in order to achieve, say, 90% power at the
0.05 nominal level". Based on the present study, we have
= (-0.064, -0.066, -0.116, -0.125, -0.135, -0.087, -0.012, 0.012)',
= (0.576, 0.225, 0.222, 0.286, 0.325, 0.296, 0.488, 0.512)' and
= (0.849 0.850, 0.810, 0.796, 0.747, 0.824, 0.977, 0.977)'. By solving equation (3), n = 157 subjects are required for each of the eight populations
under the balanced design.
(iii) Homogeneity of gametic disequilibrium among those populations in Europe.
Our statistic X2* yields 7.48 with p-value being 0.11 and T2 yields 7.26 with p-value being 0.12. Both tests do not reject the homogeneity hypothesis at the 0.05 nominal level. In this case, we have evidence to believe that populations in Europe reach their gametic equilibrium.
To end this section, we analyze the hypothetical example of gametic disequilibrium between tow loci (A, B) in ten populations described in Zapata and Alvarez [8]. Here, the gametic counts are simply set by multiplying the haplotype frequencies given in Zapata and Alvarez [8] by 1000. The data are reproduced in Table 7. Obviously, the r values are homogeneous across the ten populations. For D' values, Zapata and Alvarez [8] utilized the bias-corrected nonparametic bootstrap method to obtain the 95% confidence interval for each D' values. Observing that the resultant confidence intervals have no intersection, they concluded that D' are heterogeneous. They suggested tests for homogeneity of gametic disequilibrium should be based on D', whose range is allele probability independent, rather than r. Although, the D values in Table 7 seem to be homogeneous, our homogeneity score test yields X2* = 33.44 with p-value being less than 0.0001. Therefore, our test procedure also suggests the rejection of the homogeneity of gametic disequilibrium across the ten populations. In this case, our test reaches the same conclusion drawn by Zapata and Alvarez [8].
Table 7. Hypothetical example of gametic disequilibrium between two loci (A, B) with twoalleles (A0, A1 and B0, B1, respectively) across ten populations
Discussion
Verification of the homogeneity assumption of gametic disequilibrium across several populations is crucial in gametic disequilibrium analysis. We note that traditional homogeneity test on gametic disequilibrium is based on the Fisher's test of homogeneity among correlation coefficients. However, our simulations demonstrate that this traditional test may not perform satisfactorily. Specifically, it can be very conservative or liberal, for almost all the cases in which the common true gametic disequilibrium D is bounded away from zero. Most importantly, these kinds of conservativeness and liberty can not effectively alleviated with increased sample sizes.
Our proposed large-sample homogeneity score test on gametic disequilibrium across several independent populations requires the count of haplotypes as input. In practice, only genotype data can be obtained in most situations. To employ our method, one can use some haplotyping software, such as PHASE, HAPLOTYPER, to resolve the genotype data as haplotype data. In this way, it separates haplotype phasing and gametic disequilibrium homogeneity test. Naturally, it is more promising to extend our method which can directly handle the genotype data. In this sense, model assumptions are based on genotype data. However, the haplotype phase uncertainty for the double heterozygotes makes the definition of gametic disequilibrium can not be directly expressed by the genotype data even assuming Hardy-Weinberg equilibrium holds. It may severely affect the further derivation of the corresponding score test. Thus, extending our method to handle genotype data is an avenue we intend to explore future.
Conclusion
In this article, we propose a large-sample homogeneity test on gametic disequilibrium across several independent populations based on the likelihood score theory generalized to nuisance parameters. Our simulation results show that our test is more reliable than the traditional test based on the Fisher's test of homogeneity among correlation coefficients. Although our test may also demonstrate conservativeness and liberty in some cases, unlike the traditional test these issues can be effectively resolved by increasing sample sizes. For design purpose, sample size formula that controls power is derived.
Authors' contributions
JG initiated the study of homogeneity score test of gametic disequilibrium across strata. XLY drafted the manuscript and conducted the simulation. WQM simplified the proof in the Appendix section and made discussions extensively with XLY. MLT found a real example to apply the proposed method, proposed many constructive comments and widely polished the manuscript. All authors have read and approved the final version of this paper.
Appendix
Consistency and the condition to attain asymptotic efficiency for D*
Let nk = nbk, with bk > 0 and k = 1, 2,...,K. The asymptotic property of D* is obtained under the assumptions that K is fixed and n approaches infinity (i.e., sufficiently large). The Mantel-Haenszel-type estimator of D* can be rewritten as
where
. By the Central Limit Theorem,
has an asymptotic normal distribution N(0, Σk/bk), where yk = (x00k, x01k, x10k, x11k)/nk, gk = (p00k, p01k, p10k, p11k)',
. Let
. By δ method,
follows an asymptotic normal distribution
. It is easy to calculate that
. Since Dk ≡ D under H0 for k = 1, 2,...,K, we can conclude that D* is a consistent estimate of D. Let wk = wk(D, p1+k, p+1k), vk = 1/(p01kp10k). Thus, the asymptotic variance of D* under H0 is given by
Let the information matrix with respect to D, p1+ and p+1 under H0 be
By inverting the information matrix I, we can obtain the asymptotic variance of
, that is,
By Cauchy-Schwarz inequality
, we have AsyVar(
) = AsyVar(D*). To this end, we obtain the sufficient and necessary condition for the asymptotic
efficiency of D*, that is, wkvk = c, k = 1, 2,...,K, where c is a constant independent of all parameters. When D = 0, the condition is satisfied. From this, we know that D* is inefficient for general cases.
A simple expression for 
For the k-th stratum, denote the information matrix with respect to Dk, p1+k and p+1k by
According to the property of inverse matrix,
(Dk, p1+k, p+1k) is equal to the reciprocal of the (1, 1) element of
. By the property of MLEs, we have
where
and
are the MLEs of Dk, p1+k and p+1k, respectively. Hence, the asymptotic variance of
is
. On the contrary, by the Central Limit Theorem,
follows an asymptotic normal distribution N(0, Σk). By δ method, we immediately get that
follows an asymptotic normal distribution N(0, wk(Dk, p1+k, p+1k)). Therefore, we can obtain the exact expression
(Dk, p1+k, p+1k) = nk/wk(Dk, p1+k, p+1k). Naturally, the expression of
(D, p1+k, p+1k) is just
(Dk, p1+k, p+1k) by substituting D for Dk.
Acknowledgements
This research was supported by the National Natural Science Foundation of China (Grant Numbers 10431010 and 10701022), National 973 Key Project of China (2007CB311002), NCET-04-0310, EYTP, the Jilin Distinguished Young Scholars Program (Grant Number 20030113) and the Program Innovative Research Team (PCSIRT) in University (#IRT0519). The work of ML Tang was fully supported by a grant from the Research Grant Council of the Hong Kong Special Administration (Project no. HKBU261007).
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